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2.21x^2+0.042x-0.0379=0
a = 2.21; b = 0.042; c = -0.0379;
Δ = b2-4ac
Δ = 0.0422-4·2.21·(-0.0379)
Δ = 0.3368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.042)-\sqrt{0.3368}}{2*2.21}=\frac{-0.042-\sqrt{0.3368}}{4.42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.042)+\sqrt{0.3368}}{2*2.21}=\frac{-0.042+\sqrt{0.3368}}{4.42} $
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